oktw => #ysitd: <licson>: 所以 e^iπ = cos π + i sin π = 1 + 0i = 1 #56a0a5f14d9f22652490c434

oktw says to #ysitd

<licson>: 所以 e^iπ = cos π + i sin π = 1 + 0i = 1

at Thu, Jan 21, 2016 5:33 PM